Class 6: Maths Chapter 2 solutions. Complete Class 6 Maths Chapter 2 Notes.
NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers
NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions
Page No: 31
Exercise 2.1
1. Write the next three natural numbers after 10999.
Answer
11000 , 11001, 11002
2. Write the three whole numbers occurring just before 10001.
Answer
10000, 9999,9998
3. Which is the smallest whole number?
Answer
0 is the smallest whole number.
4. How many whole numbers are there between 32 and 53?
(33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52)
There are 20 whole numbers lie between 32 and 53.
5. Write the successor of :
(a) 2440701
(b) 100199
(c) 1099999
(d) 2345670
Answer
a) 2440701 = 2440701 + 1 = 2440702.
b) 100199 = 100199 + 1 = 100200
c) 1099999 = 1099999 + 1 = 1100000
d) 2345670 = 2345670 + 1 = 2345671
6. Write the predecessor of :
(a) 94
(b) 10000
(c) 208090
(d) 7654321
Answer
(a) 94 = 94 – 1 = 93
(b) 10000 = 10000 – 1= 9999
(c) 208090 = 208090 – 1 = 208089
(d) 7654321 = 7654321 – 1 = 76543210
7. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>,< ) between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001
Answer
(a) 530 > 503
530 is on the left side of number line.
(b) 370 > 307
370 is on the left side of number line.
(c) 98765 > 56789
98765 is on the left side of the number line
(d) 9830415 < 10023001
10023001 is the left side of the number line.
8. Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.
Answer
(a) 0 is not a natural number (false)
(b) Predecessor of 399 is 398 (false)
(c) True
(d) 599 + 1 = 600 (true)
(e) True
(f) 0 is whole number but not natural numbers.(false)
(g) False
(h) 0 is the smallest whole number (false)
(i) True
(j) False
(k) False
(l) True
(m) False
Page No: 40
Exercise 2.2
1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647
Answer
(a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408
(b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (647 + 453)
= 3500 + 1100 = 4600
2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25
Answer
(a) 2 × 50 × 1768 = 176,800
(b) 166 × 25 × 4 = 16600
(c) 291 × 125 × 8 = 291000
(d) 285 × 60 × 5 = 2790000
(e) 285 × 60 × 3 = 85500
(f) 125 × 40 × 25 × 8 = 1000000
3. Find the value of the following:
(a) 297 × 17 + 297 × 3
(b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69
(d) 3845 × 5 × 782 + 769 × 25 × 218
Answer
(a) 297 × (17 + 3 ) = 297 × 20 = 5940.
(b) 54279 × (92 + 8)
= 54279 × 100 = 5427900.
(c) 81265 × (169 – 69)
81265 × 100 = 8126500
(d) 3845 × 5 × 782 + 769 × 5 × 5 × 218
= 3845 × 5 × (782 + 218)
= 19225 × 1000 = 19225000.
4. Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168
Answer
(a) 738 × 103
= (738 × 100) + (738 × 3)
= 73800 + 2214 = 76014
(b) 854 × 102
= (854 × 100) + (854 × 2)
= 85400 + 1708 = 87108
(c) 258 × 1008
= (258 × 1000) + (258 × 8)
= 258000 + 2064 = 260064
(d) 1005 × 168 = (1000 + 5) × 168
= (1000 × 168) + (5 × 168)
= 168000 + 840 = 168840
5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?
Answer
Petrol filled on Monday = 40 litres
Petrol next day filled = 50 litres
Total quantity of petrol filled = (40 +50) litres
Cost of petrol per litres = 44
Total amount of money spent on petrol = 44 × (40 + 50)
= 44 × 90 = Rs 3960
Page No: 41
6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day?
Answer
In the morning vendor supplies = 32 litres.
In the evening vendor supplies = 68 litres.
Cost of milk per litre = Rs 15
Total cost of per day = 15 × ( 32 + 68)
= 15 × 100 = Rs 1500
7. Match the following:
Answer
(i) ➝ C
(ii) ➝ A
(iii) ➝ B
Page No: 43
Exercise 2.3
1. Which of the following will not represent zero:
(a) 1 + 0
(b) 0 × 0
(c) 0 / 2
(d) (10 - 10)/2
Answer
(a) 1 + 0 = 1 (not represent zero)
(b) 0 × 0 = 0 (it represent zero)
(c) 0 / 2 = 0 (it represent zero)
(d) (10 – 10)/ 2 = 0 (it represent zero)
2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.
Answer
Product of two whole number is zero then both of them may be zero
0 × 3 =0
1 × 3 = 3
3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.
Answer
Product of two whole number is 1 , both number is equal to 1.
For example , 1 × 1 = 1 , 1 × 6 = 6
In both example, number is multiplied by 1.
4. Find using distributive property :
(a) 728 × 101
(b) 5437 × 1001
(c) 824 × 25
(d) 4275 × 125
(e) 504 × 35
Answer
(a) 728 × 101
= (728 × 100) + (728 × 1)
= 72800 + 728
= 73528
(b) 5437 × 1001
= (5437 × 1000) + (5437 × 1)
= 5437000 + 5437
= 5442437
(c) 824 × 25
= (800 + 24) × 25
= (800 + 25 – 1) × 25
= (800 × 25) + ( 25 × 25) – (1 × 25)
= (20000 × (625 – 25)
= 20000 + 600 = 20600
(d) 4275 × 125
= (4000 + 25 + 200 + 50) × (100 + 25)
= (4000×100) + (25×100) + (200×100) + (50×100) + (4000×25) + (25×25) + (200×25) + (50×25)
= 400000 + 2500 + 20000 + 5000 + 100000 + 625 + 5000 + 1250
= 534375
(e) 504 × 35
= (500 + 4) × 35
= (500 × 35) + (4 × 35)
= 17500 + 140 = 17640
5. Study the pattern : 1 × 8 + 1 = 9
1234 × 8 + 4 = 9876
12 × 8 + 2 = 98
12345 × 8 + 5 = 98765
123 × 8 + 3 = 987
Write the next two steps. Can you say how the pattern works? (Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
Answer
123456 × 8 + 6 = 987648 + 6 = 987654
1234567 × 8 + 7 = 9876536 + 7 = 9876543
Pattern are use in following ways
123456 = 123456 × 8 (111111+11111+1111+111+11+1) × 8
= 111111 × 8 + 11111 × 8 +1111 × 8 + 111 × 8 + 11 × 8 + 1× 8
= 888888 + 88888 +8888 +888 +88 + 8 = 987648
123456 × 8 +6 = 987648 + 6 = 987654
NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions
NCERT Solutions for 6th Class Maths: Chapter 2: Download PDF
NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers
Download PDF: NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers PDF
Chapterwise NCERT Solutions for Class 6 Maths :
- Chapter 1 Knowing Our Numbers
- Chapter 2 Whole Numbers
- Chapter 3 Playing with Numbers
- Chapter 4 Basic Geometrical Ideas
- Chapter 5 Understanding Elementary Shapes
- Chapter 6 Integers
- Chapter 7 Fractions
- Chapter 8 Decimals
- Chapter 9 Data Handling
- Chapter 10 Mensuration
- Chapter 11 Algebra
- Chapter 12 Ratio and Proportion
- Chapter 13 Symmetry
- Chapter 14 Practical Geometry
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