RS Aggarwal Solutions for Class 9 Maths Chapter 2–Polynomials

Class 9: Maths Chapter 2 solutions. Complete Class 9 Maths Chapter 2 Notes.

RS Aggarwal Solutions for Class 10 Maths Chapter 2–Polynomials

RS Aggarwal 9th Maths Chapter 2, Class 9 Maths Chapter 2 solutions

Ex 2A Solutions

Question 1.
Solution:
(i) x⁵-2x³+x+7 is a polynomial and its degree is 5
(ii) y³-√3y is a polynomial and its degree is 3

Question 2.
Solution:
(i) Degree is 1
(ii) degree is 3
(iii) degree is zero
(iv) degree is 7
(v) degree is 10
(vi) degree is 2

Question 3.
Solution:
(i) Coefficient of x³ is -5.
(ii) Coefficient of x is -2√2
(iii) Coefficient of x² is π3
(iv) Coefficient of x² is 0

Question 4.
Solution:
(i) Example of a binomial of degree 27 is 4x²⁷ – 5
(ii) Example of a monomial of degree 16 is x¹⁶
(iii) Example of trinomial of degree 3 is 2x³ + 7x + 4

Question 5.
Solution:
(i) 2x² + 4x is a quadratic polynomial. (Degree 2)
(ii) x – x³ is a cubic polynomial (Degree 3)
(iii) 2 – y – y² is a quadratic polynomial (Degree 2)
(iv) – 7 + z is a linear polynomial (Degree 1)
(v) 5t is a linear polynomial (Degree 1)
(vi) p³ is a cubic polynomial (Degree 3)

Ex 2B Solutions

Question 1.
Solution:
p(x) = 5 – 4x + 2x²

Question 2.
Solution:
p(y) = 4 + 3y – y² + 5y³

Question 3.
Solution:
f(t)=4t²-3t+6

Question 4.
Solution:

Question 5.
Solution:

Ex 2C

Question 1.
Solution:
f(x) = (x³ – 6x² + 9x + 3)
Let x-1 = 0, then x = 1

Question 2.
Solution:
f(x) = 2x³ – 5x² + 9x – 8)
Let x-3 = 0, then x = 3

Question 3.
Solution:
f(x) = (3x⁴ – 6x² – 8x + 2)
Let x-2 = 0, the x = 2

Question 4.
Solution:
f(x) = (x³ – 7x² + 6x + 4)
Let x-6 = 0,then x=6

Question 5.
Solution:
f(x)=(x³ – 6x² + 13x + 60)
Let x+2=0,then x=-2

Question 6.
Solution:
f(x)=(2x⁴ + 6x³ + 2x² + x – 8)
Let x+3=0,then x=-3

Question 7.
Solution:
f(x)=(4x³ – 12x² + 11x – 5)

Question 8.
Solution:
f(x)=(81x⁴ + 54x³ – 9x² – 3x + 2)

Question 9.
Solution:
f(x)=(x³ – ax² + 2x – a)
let x-a=0, then x=a

Question 10.
Solution:
f(x)=(ax³+ 3x² – 3)
g(x)=(2x³ -5x + a)

Question 11.
Solution:
f(x)=x⁴ – 2x³ + 3x² – ax + b
let x-1=0, then x=1

Question 1.
Solution:
By factor theorem, x – 2 will be a factor of f(x) = x³ – 8 if f(2) = 0
(∴ x-2 = 0=>x = 2)
Now f(2) = (2)³ – 8 = 8- 8 = 0
Hence (x – 2) is a factor of f(x) Ans.

Question 2.
Solution:
By factor theorem,

Question 3.
Solution:
By factor theorem,
(x – 1) is a factor of f(x)=(2x⁴ + 9x³ + 6x²– 11x – 6)

Question 4.
Solution:
By factor theorem, (x + 2) will
a factor of f (x) = x⁴ – x⁴ + 2

Question 5.
Solution:
By factor theorem, (x + 5) will be a factor of f(x) = 2x³ + 9x² – 11x – 30 if f(-5) = 0

Question 6.
Solution:
By factor theorem, (2x – 3) is a factor of f(x) = 2x⁴ + x³ – 8x² – x + 6

Question 7.
Solution:
By factor theorem, (x – √2 ) will be a factor of f(x) = 7x² – 4√2x – 6

Question 8.
Solution:
By factor theorem, (x + √2) will be a factor of f(x) = 2√2 x³ + 5x + √2

Question 9.
Solution:
Let f(x) = 2x³ + 9x² + x + k and x – 1 is a factor of f(x)

Question 10.
Solution:
Let f(x) = 2x³ – 3x² – 18x + a and x – 4 is its factor

Question 11.
Solution:
Let f(x) – x⁴ – x³ – 11x² – x + a
f(x) is divisible by (x + 3)

Question 12.
Solution:
Let f(x) = 2x³ + ax² + 11x + a + 3
and (2x – 1) is its factor
Let 2x – 1 = 0 then 2x = 1

Question 13.
Solution:
Let f(x) = x³ – 10x² + ax + b and (x – 1) and (x – 2) are its factors
∴ x – 1 = 0 =>x=1
and x – 2 = 2 =>x=2

Question 14.
Solution:
Let f(x) = x⁴ + ax³ – 7x² – 8x + b ,
and (x + 2) and (x + 3) are its factors
∴x + 2 = 0 => x = -2
and x + 3= 0 => x = -3

Question 15.
Solution:
Let f(x) = x³ – 3x² – 13x + 15
Now x² + 2x – 3 = x² + 3x – x – 3

Question 16.
Solution:
Let f(x) = x³ + ax² + bx + 6 and (x – 2) is its factor
Let x – 2 = 0 then x = 2

Ex 2E

Factorize:

Question 1.
Solution:
9x² + 12xy
= 3x (3x + 4y) Ans.

Question 2.
Solution:
18x²y – 24xyz
= 6xy (3x – 4z) Ans.

Question 3.
Solution:
27a³b³ – 45a⁴b²
= 9a³b² (3b – 5a) Ans.

Question 4.
Solution:
2a (x + y) – 3b(x + y)
= (x + y) (2a – 3b) Ans.

Question 5.
Solution:
2x (p² + q²) + 4y (p² + q²)
= 2(p² + q²) (x + 2y) Ans

Question 6.
Solution:
x (a – 5) + y (5 – a)
= x (a – 5) -y (a – 5)
= (a – 5) (x – y) Ans.

Question 7.
Solution:
4(a + b) – 6 (a + b)²
= 2(a + b) {2 – 3 (a + b)}
= 2(a + b) (2 – 3a – 3b) Ans.

Question 8.
Solution:
8(3a – 2b)² – 10 (3a – 2b)
= 2(3a – 2b) {4 (3a – 2b) – 5}
= 2(3a – 2b) (12a – 8b – 5) Ans.

Question 9.
Solution:
x (x + x)³ – 3x² y (x + y)
= x (x + y) {(x + y)² – 3xy}
= x (x + y) [x² + y² + 2xy – 3xy)
= x (x + y) (x² + y² – xy) Ans.

Question 10.
Solution:
x³ + 2x² + 5x + 10
= x² (x + 2) + 5 (x + 2)
= (x + 2) (x² + 5) Ans.

Question 11.
Solution:
x² + xy – 2xz – 2yz
= x (x + y) -2z (x + y)
= (x + y) (x – 2z) Ans.

Question 12.
Solution:
a³ b – a²b + 5ab – 5b.
= b (a³ – a² + 5a – 5)
= b {(a² (a – 1) + 5 (a – 1)}
= b (a – 1) (a² + 5) Ans.

Question 13.
Solution:
8 – 4a – 2a³ + a⁴
= 4 (2 – a) – a³ (2 – a)
= (2 – a) (4 – a³) Ans.

Question 14.
Solution:
x³ – 2x²y + 3xy² – 6y³
= x² (x – 2y) + 3y² (x – 2y)
= (x – 2y) (x² + 3y²) Ans

Question 15.
Solution:
px – 5q + pq – 5x
= px – 5x + pq – 5q
= x(p – 5) + q(p – 5)
= {p – 5) (x + q) Ans.

Question 16.
Solution:
x² + y – xy – x
= x² – x – xy + y
= x (x – 1) – y (x – 1)
= (x – 1) (x – y) Ans.

Question 17.
Solution:
(3a – 1)² – 6a + 2
= (3a – 1)² – 2 (3a – 1)
= (3a – 1) (3a – 1 – 2)
= (3a – 1) (3a – 3)
= 3(3a – 1) (a – 1) Ans.

Question 18.
Solution:
(2x – 3)² – 8x + 12
= (2x – 3)² – 4(2x – 3)
= (2x – 3) (2x – 3 – 4)
= (2x – 3) (2x – 7) Ans.

Question 19.
Solution:
a3 + a – 3a2 – 3
= a3 – 3a2 + a – 3
= a2 (a – 3) + 1 (a – 3)
= (a – 3) (a2 + 1) Ans.

Question 20.
Solution:
3ax – 6ay – 8by + 4bx
= 3ax – 6ay + 4bx – 8by
= 3a (x – 2y) + 4b (x – 2y)
= (x – 2y) (3a + 4b) Ans

Question 21.
Solution:
abx² + a²x + b²x + ab
= ax (bx + a) + b (bx + a)
= (bx + a) (ax + b) Ans.

Question 22.
Solution:
x³ – x² + ax + x – a – 1
= x³ – x² + ax – a + x – 1
= x² (x – 1) + a (x – 1) + 1 (x – 1)
= (x – 1) (x² + a + 1) Ans.

Question 23.
Solution:
2x + 4y – 8xy – 1
= 2x – 8xy -1+4y
= 2x (1 – 4y) -1 (1 – 4y)
= (1 – 4y) (2x – 1) Ans.

Question 24.
Solution:
ab (x² +y²) – xy (a² + b²)
= abx² + aby² – a²xy – b²xy
= abx² – a²xy – b²xy + aby²
= ax (bx – ay) – by (bx – ay)
= (bx – ay) (ax – by) Ans.

Question 25.
Solution:
a² + ab (b + 1) + b³
= a² + ab² + ab + b³
= a (a + b²) + b (a + b²)
= (a + b²) (a + b) Ans

Question 26.
Solution:
a³ + ab (1 – 2a) – 2b²
= a³ + ab – 2a²b – 2b²
= a³ – 2a²b + ab – 2b²
= a² (a – 2b) + b (a – 2b)
= (a – 2b) (a² + b) Ans.

Question 27.
Solution:
2a² + bc – 2ab – ac
= 2a² – 2ab – ac + bc
= 2a (a – b) – c (a – b)
= (a – b) (2a – c) Ans.

Question 28.
Solution:
(ax + by)² + (bx – ay)²
= a²x² + b²y² + 2abxy + b²x² + a²y² – 2bxy
= a²x² + b²y² + b²x² + a²y²
= a²x² + b²x² + a²y² + b²y²
= x2(a2 + b2) + y2(a2 + b2)
= (a² + b²) (x² + y²) Ans.

Question 29.
Solution:
a (a + b – c) – bc
= a² + ab – ac – bc
= a (a + b) – c (a + b)
(a + b) (a – c) Ans.

Question 30.
Solution:
a(a – 2b – c) + 2bc
= a² – 2ab – ac +2bc
= a² – ac – 2ab + 2bc
= a (a – c) – 2b (a – c)
= (a – c) (a – 2b) Ans.

Question 31.
Solution:
a²x² + (ax² + 1) x + a
= a²x² + ax³ + x + a
= a²x² + ax³ + a + x
= ax² (a + x) + 1 (a + x)
– (a + x) (ax² + 1) Ans

Question 32.
Solution:
ab (x² + 1) + x (a² + b²)
= abx² + ab + a²x + b²x
= abx² + a²x + b²x + ab
= ax (bx + a) + b (bx + a)
= (bx + a) (ax + b) Ans.

Question 33.
Solution:
x² – (a + b) x + ab
= x² – ax – bx + ab
= x (x – a) – b (x – a)
= (x – a) (x – b) Ans.

Question 34.
Solution:

Ex 2F

Question 1.
Solution:
25x² – 64y²
= (5x)² – (8y)²
= (5x + 8y) (5x – 8y) Ans.

Question 2.
Solution:
100 – 9x²
(10)² – (3x)²
= (10 + 3x) (10 – 3x) Ans.

Question 3.
Solution:
5x² – 7y²
=(√5x)² +(√7y)²
=(√5x – √7y)(√5x – √7y) Ans

Question 4.
Solution:
(3x + 5y)² – 4z²
= (3x + 5y)² – (2z)²
= (3x + 5y + 2z) (3x + 5y – 2z) Ans.

Question 5.
Solution:
150 – 6x²
= 6(25 – x²)
= 6{(5)² – (x²)}
= 6 (5 + x) (5 – x) Ans.

Question 6.
Solution:
20x² – 45
= 5 (4x² – 9)
= 5{(2x)² – (3)²}
= 5 (2x + 3) (2x – 3) Ans.

Question 7.
Solution:
3x³ – 48x
= 3x (x² – 16)
= 3x {(x)² – (4)²}
= 3x (x + 4) (x – 4) Ans.

Question 8.
Solution:
2 – 50x²
= 2(1 – 25x²) = 2 {(1)² – (5x)²}
= 2 (1 + 5x) (1 – 5x) Ans.

Question 9.
Solution:
27a² – 48b²
= 3(9a² – 16b²)
= 3 {(3a)² – (4b)²}
= 3(3a + 4b) (3a – 4b) Ans.

Question 10.
Solution:
x – 64x³
= x (1 – 64x²)
= x{(1)² – (8x)²}
= x (1 + 8x) (1 – 8x) Ans.

Question 11.
Solution:
8ab² – 18a³
= 2a (4b² – 9a²)
= 2a {(2b)² – (3a)²}
= 2a (2b + 3a) (2b – 3a) Ans

Question 12.
Solution:
3a³b – 243ab³
= 2ab (a² -81 b²)
= 3ab {(a)² – (9b)²}
= 3ab (a + 9b) (a – 9b) Ans.

Question 13.
Solution:
(a + b)³ – a – b
= (a + b)³ – 1 (a + b)
= (a + b) {(a + b)² – 1}
= (a + b) {(a + b)² – (1)²}
= (a + b) (a + b + 1) (a + b – 1) Ans.

Question 14.
Solution:
108 a² – 3(b – c)²
= 3 {36a² – (b – c)²}
= 3 {(6a)² – (b – c)²}
= 3 {(6a + (b – c)} {6a – (b – c)}
= 3 (6a + b – c) (6a – b + c) Ans.

Question 15.
Solution:
x³ – 5x² – x + 5
= x²(x – 5) -1(x – 5)
= (x – 5) (x² – 1)
= (x – 5) {(x)² – (1)²}
= (x – 5) (x + 1) (x – 1) Ans.

Question 16.
Solution:
a² + 2ab + b² – 9c²
= (a + b)² – (3c)²
= {a² + b² + 2ab – (a + b)²}
= (a + b + 3c) (a + b – 3c) Ans.

Question 17.
Solution:
9 – a² + 2ab – b²
= 9 – (a² – 2ab + b²)
= (3)² -(a- b)²
{ ∴a² + b² – 2ab = (a – b)²}
= (3 + a – b) (3 – a + b) Ans.

Question 18.
Solution:
a² – b² – 4ac + 4c²
= a² – 4ac + 4c² – b²
= (a)² – 2 x a x 2c + (2c)² – (b)²
= (a – 2c)² – (b)²
= (a – 2c + b) (a – 2c – b)
= (a + b – 2c) (a – b – 2c) Ans.

Question 19.
Solution:
9a² + 3a – 8B – 64b²
= 9a² – 64b² + 3a – 8b
= (3a)² – (8b)² + 1(3a – 8b)
= (3a + 8b) (3a – 8b) + 1 (3a – 8b)
= (3a – 8b) (3a + 8b + 1) Ans.

Question 20.
Solution:
x² – y² + 6y _ 9
= (x)2 – (y² – 6y + 9)
= (x)2 – {(y)² – 2 x y x 3 + (3)²}
= (x)² – (y – 3)²
= (x + y – 3) (x – y + 3) Ans.

Question 21.
Solution:
4x² – 9y² – 2x – 3y
= (2x)² – (3y)² – 1(2x + 3y)
= (2x + 3y) (2x – 3y) – 1( 2x + 3y)
= (2x + 3y) (2x – 3y – 1) Ans.

Question 22.
Solution:
x⁴ – 1
= (x²)² – (1)²
= (x² + 1) (x² – 1)
= (x² + 1) {(x)² – (1)²}
= (x² + 1) (x + 1) (x – 1) Ans.

Question 23.
Solution:
a – b – a²+ b²
= 1 (a – b) – (a² – b²)
= 1 (a – b) – (a + b) (a – b)
= (a – b) (1 – a – b) Ans.

Question 24.
Solution:
x⁴ – 625
= (x²)² – (25)²
= (x² + 25) (x² – 25)
= (x² + 25) {(x)² – (5)²}
= (x² + 25) (x + 5) (x – 5) Ans.

Ex 2G

Question 1.
Solution:
x² + 11x + 30

Question 2.
Solution:
x² + 18x + 32

Question 3.
Solution:
x² + 7x – 18

Question 4.
Solution:
x² + 5x – 6

Question 5.
Solution:
y² – 4y + 3

Question 6.
Solution:
x² – 21x + 108

Question 7.
Solution:
x² – 11x – 80

Question 8.
Solution:
x² – x – 156

Question 9.
Solution:
z² – 32z – 105

Question 10.
Solution:
40 + 3x – x²

Question 11.
Solution:
6 – x – x²

Question 12.
Solution:
7x² + 49x + 84

Question 13.
Solution:
m² + 17mn – 84n²

Question 14.
Solution:
5x² + 16x + 3

Question 15.
Solution:
6x² + 17x + 12

Question 16.
Solution:
9x² + 18x + 8

Question 17.
Solution:
14x² + 9x + 1

Question 18.
Solution:
2x² + 3x – 90

Question 19.
Solution:
2x² + 11x – 21

Question 20.
Solution:
3x² – 14x + 8

Question 21.
Solution:
18x² + 3x- 10

Question 22.
Solution:
15x² + 2x – 8

Question 23.
Solution:
6x² + 11x – 10

Question 24.
Solution:

Question 25.
Solution:
24x² – 41x + 12

Question 26.
Solution:
2x² – 7x – 15

Question 27.
Solution:
6x² – 5x – 21

Question 28.
Solution:
10x² – 9x – 7

Question 29.
Solution:
5x² – 16x – 21

Question 30.
Solution:
2x² – x – 21

Question 31.
Solution:
15x² – x – 28

Question 32.
Solution:
8a² – 27ab + 9b²

Question 33.
Solution:
5x² + 33xy -14y²

Question 34.
Solution:
3x³ – x² – 10x

Question 35.
Solution:

Question 36.
Solution:

Question 37.
Solution:
√2x² + 3x + √2

Question 38.
Solution:
√5x² + 2x – 3√5

Question 39.
Solution:
2a² + 3√3x + 3

Question 40.
Solution:
2√3x² + x – 5√3

Question 41.
Solution:
5√5x² + 20x + 3√5

Question 42.
Solution:
7√x² – 10x – 4√2

Question 43.
Solution:
6√3 x² – 47x + 5√3

Question 44.
Solution:
7x² + 2√14x + 2

Question 45.
Solution:
2(x + y)² – 9(x + y) – 5

Question 46.
Solution:
9(2a-b)²-4(2a-b)-13

Question 47.
Solution:
7(x – 2y)² – 25 (x – 2y) + 12

Question 48.
Solution:
4x⁴ + 7x²-2

Ex 2H

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:
9x² + 16y² + 4z² – 24xy + 16yz – 12xz

Question 5.
Solution:
25x² + 4y² + 9z² – 20xy – 12yz + 30xz

Question 6.
Solution:

Ex 2I

Question 1.
Solution:
(i)(3x+2)³

Question 2.
Solution:

Question 3.
Solution:
(i)(95)³ = (100 – 5)³

Ex 2J

Question 1.
Solution:
x³ + 27
= (x)³ + (3)³

Question 2.
Solution:
8x³ + 27y³

Question 3.
Solution:
343 + 125b³

Question 4.
Solution:
(1)³+(4x)³

Question 5.
Solution:
125a³+ 18

Question 6.
Solution:
216x³+1125

Question 7.
Solution:
16x⁴ + 54x

Question 8.
Solution:
7a³ + 56b³
=7(a³+8b³)

Question 9.
Solution:
x⁵ + x²
=x²(x³+1)

Question 10.
Solution:
a³ + 0.008

Question 11.
Solution:
x⁶ + y⁶

Question 12.
Solution:
2a³ + 16b³ – 5a – 10b

Question 13.
Solution:
x³ – 512
=(x)³ – (8)³

Question 14.
Solution:
64x³ – 343
=(4x)³ – (7)³

Question 15.
Solution:
1 – 27x³
=(1)³– (3x)³

Question 16.
Solution:
x³ – 125y³

Question 17.
Solution:
8x³ – 127y3

Question 18.
Solution:
a³ – 0.064
=(a)³ – (0.4)³

Question 19.
Solution:
(a + 6)³ – 8
=(a+b)³ – (2)³

Question 20.
Solution:
x⁶ – 729
=(x²)³ – (9)³

Question 21.
Solution:
(a + b)³ – (a – b)³

Question 22.
Solution:
x – 8xy³
=x(1 – 8y³)
=x{(1)³ – (2y)³}

Question 23.
Solution:
32x⁴ – 500x

Question 24.
Solution:
3a⁷b – 81a⁴ b⁴

Question 25.
Solution:
a3−1a3−2a+2a

Question 26.
Solution:
8a³ – b³ – 4ax + 2bx

Question 27.
Solution:
a³ + 3a²b + 3ab² + b³ – 8

Ex 2K

Question 1.
Solution:
125a³ + b³ + 64c³ – 60abc

Question 2.
Solution:
a³ + 8b³ + 64c³ – 24abc

Question 3.
Solution:
1 + b³ + 8c³ – 6bc

Question 4.
Solution:
216 + 27b³ + 8c³ – 108bc

Question 5.
Solution:
27a³ – b³ + 8c³ + 18abc

Question 6.
Solution:
8a³ + 125b³ – 64c³ + 120abc

Question 7.
Solution:
8 – 27b³ – 343c³ – 126bc

Question 8.
Solution:
125 – 8x³ – 27y³ – 90xy

Question 9.
Solution:
2√2a³ + 16√2b³ + c³ – 12abc

Question 10.
Solution:
x³ + y³ – 12xy + 64

Question 11.
Solution:
(a – b)³ + (b – c)³ + (c – a)³

Question 12.
Solution:
(3a – 2b)³ + (26 – 5c)³ + (5c – 3a)³

Question 13.
Solution:
a³ (b – c)³ + b³ (c – a)³ + c³ (a – b)³

Question 14.
Solution:
(5a – 7b)³ + (9c – 5a)³ + (7b – 9c)³

Question 15.
Solution:
(x + y – z) (x² + y² + z² – xy + yz + zx)

Question 16.
Solution:
(x – 2y + 3) (x² + 4y² + 2xy -3x + 6y + 9)

Question 17.
Solution:
(x – 2y – z) (x² + 4y² + z² + 2xy + zx- 2yz)

Question 18.
Solution:
x + y + 4 = 0,

Question 19.
Solution:
x = 2y + 6

RS Aggarwal Solutions for Class 9 Maths Chapter 2: Download PDF

RS Aggarwal Solutions for Class 9 Maths Chapter 2–Polynomials

Download PDF: RS Aggarwal Solutions for Class 9 Maths Chapter 2–Polynomials PDF

Chapterwise RS Aggarwal Solutions for Class 9 Maths :

• Chapter 1–Real Numbers
• Chapter 2–Polynomials
• Chapter 3–Introduction to Euclid’s Geometry
• Chapter 4–Lines and Triangles
• Chapter 5–Congruence of Triangles and Inequalities in a Triangle
• Chapter 6–Coordinate Geometry
• Chapter 7–Areas
• Chapter 8–Linear Equations in Two Variables
• Chapter 9–Quadrilaterals and Parallelograms
• Chapter 10–Area
• Chapter 11–Circle
• Chapter 12–Geometrical Constructions
• Chapter 13–Volume and Surface Area
• Chapter 14–Statistics
• Chapter 15–Probability

About RS Aggarwal Class 9 Book

Investing in an R.S. Aggarwal book will never be of waste since you can use the book to prepare for various competitive exams as well. RS Aggarwal is one of the most prominent books with an endless number of problems. R.S. Aggarwal's book very neatly explains every derivation, formula, and question in a very consolidated manner. It has tonnes of examples, practice questions, and solutions even for the NCERT questions.

He was born on January 2, 1946 in a village of Delhi. He graduated from Kirori Mal College, University of Delhi. After completing his M.Sc. in Mathematics in 1969, he joined N.A.S. College, Meerut, as a lecturer. In 1976, he was awarded a fellowship for 3 years and joined the University of Delhi for his Ph.D. Thereafter, he was promoted as a reader in N.A.S. College, Meerut. In 1999, he joined M.M.H. College, Ghaziabad, as a reader and took voluntary retirement in 2003. He has authored more than 75 titles ranging from Nursery to M. Sc. He has also written books for competitive examinations right from the clerical grade to the I.A.S. level.

FAQs

Why must I refer to the RS Aggarwal textbook?
RS Aggarwal is one of the most important reference books for high school grades and is recommended to every high school student. The book covers every single topic in detail. It goes in-depth and covers every single aspect of all the mathematics topics and covers both theory and problem-solving. The book is true of great help for every high school student. Solving a majority of the questions from the book can help a lot in understanding topics in detail and in a manner that is very simple to understand. Hence, as a high school student, you must definitely dwell your hands on RS Aggarwal!

Why should you refer to RS Aggarwal textbook solutions on Indcareer?
RS Aggarwal is a book that contains a few of the hardest questions of high school mathematics. Solving them and teaching students how to solve questions of such high difficulty is not the job of any neophyte. For solving such difficult questions and more importantly, teaching the problem-solving methodology to students, an expert teacher is mandatory!

Does IndCareer cover RS Aggarwal Textbook solutions for Class 6-12?
RS Aggarwal is available for grades 6 to 12 and hence our expert teachers have formulated detailed solutions for all the questions of each edition of the textbook. On our website, you'll be able to find solutions to the RS Aggarwal textbook right from Class 6 to Class 12. You can head to the website and download these solutions for free. All the solutions are available in PDF format and are free to download!

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