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Selina Class 9 ICSE Solutions Mathematics : Chapter 15- Construction of Polygons

Class 9: Maths Chapter 15 solutions. Complete Class 9 Maths Chapter 15 Notes. Selina Class 9 ICSE Solutions Mathematics : Chapter 15- Construction of Polygons Selina 9th Maths Chapter 15, Class 9...

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Applicable Grade Class 9
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Class 9: Maths Chapter 15 solutions. Complete Class 9 Maths Chapter 15 Notes.

Selina Class 9 ICSE Solutions Mathematics : Chapter 15- Construction of Polygons

Selina 9th Maths Chapter 15, Class 9 Maths Chapter 15 solutions

Solution 1:
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Solution 2:
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Solution 9:
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Solution 10:
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Solution 15:
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Solution 23:
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Steps:

  1. We construct the segment AC = 7cm.
  2. With A as a centre and radius 5.4 cm , we draw an arc extending on both sides of AC.
  3. With C as centre and same radius as in step 2, we draw an arc extending on both sides of AC to cut the first arc at B and D.
  4. Join AB,BC,CD and DA.

ABCD is the required rhombus.

Solution 24:
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Solution 36:
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Solution 37:
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Steps:

  1. Draw a base line AQ.
  2. From A take some random distance in compass and draw one are below and above the line. Now without changing the distance in compass draw one are below and above the line. These arcs intersect each other above and below the line.
  3. Draw the line passing through these intersecting points, you will get a perpendicular to the line AQ.
  4. Take distance of 4 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AQ passing through through this arc.
  5. From point A measure an angle of 60 degree and draw the line which intersect above drawn line at some point label it as D.
  6. Using the procedure given in step 2 again draw a perpendicular to line AD.
  7. Take distance of 3 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AD passing through through this arc which intersect the line AQ at some point label it as B and to other line at point C.

ABCD is the required parallelogram.

Solution 38:
To draw the parallelogram follows the steps:

  1. First draw a line AB of measure 6cm. Then draw an angle of measure 450 at point A such that ∠DAB = 450 and AD = 5cm.
  2. Now draw a line CD parallel to the line AB of measure 6cm. Then join BC to construct the parallelogram as shown below:
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Solution 39:
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Selina Class 9 ICSE Solutions Mathematics : Chapter 15- Construction of Polygons

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