ML Aggarwal Solutions for Class 7 Maths Chapter 4- Exponents and Powers

Class 7: Maths Chapter 4 solutions. Complete Class 7 Maths Chapter 4 Notes.

ML Aggarwal Solutions for Class 7 Maths Chapter 4- Exponents and Powers

ML Aggarwal 7th Maths Chapter 4, Class 7 Maths Chapter 4 solutions

1. Fill in the blanks:

(i) In the expression 3⁷, base = …. And exponent = …..

Solution:-

In the expression 3⁷, base = 3 and exponent = 7

(ii) In the expression (-7)⁵, base = ….. and exponent = ……

Solution:-

In the expression (-7)⁵, base = -7 and exponent = 5

(iii) In the expression (2/5)¹¹ base = …. And exponent = …..

Solution:-

In the expression (2/5)¹¹, base = 2/5 and exponent = 11

(iv) If base is 6 and exponent is 8, then exponential form = ____

Solution:-

If base is 6 and exponent is 8, then exponential form = 6⁸

2. Find the value of the following:

(i) 2⁶

Solution:-

2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64

(iii) 5⁵

Solution:-

5⁵ = 5 × 5 × 5 × 5 × 5 = 3125

(iii) (-6)⁴

Solution:-

-6 × – 6 × -6 × -6 = 1296

(iv) (2/3)⁴

Solution:-

(2/3) × (2/3) × (2/3) × (2/3) = 16/81

(v) (-2/3)⁵

Solution:-

(-2/3)⁵ = (-2/3) × (-2/3) × (-2/3) × (-2/3) × (-2/3) = -32/729

(vi) (-2)⁹

Solution:-

-2 × -2 × -2 × -2 × -2 × -2 × -2 × -2 × -2 = -512

3. Express the following in the exponential form:

(i) 6 x 6 x 6 x 6 x 6

Solution:-

6 x 6 x 6 x 6 x 6 = 6⁵

(ii) t x t x t

Solution:-

t x t x t = t³

(iii) 2 x 2 x a x a x a x a

Solution:-

2 x 2 x a x a x a x a = 2²a⁴

(iv) a x a x a x c x c x c x c x d

Solution:-

a x a x a x c x c x c x c x d = a³c⁴d

4. Simplify the following

(i) 7 x 10³

Solution:-

Above question can be written as,

= 7 x 10 x 10 x 10

= 7 x 1000

= 7000

(ii) 2⁵ x 9

Solution:-

Above question can be written as,

= 2 x 2 x 2 x 2 x 2 x 9

= 32 x 9

= 288

(iii) 3³ x 10⁴

Solution:-

Above question can be written as,

= 3 x 3 x 3 x 10 x 10 x 10 x 10

= 27 x 10000

= 2,70,000

5. Simplify the following

(i) (-3) x (-2)³

Solution:-

Above question can be written as,

= (-3) x (-2) x (-2) x (-2)

= (-3) x (-8)

= 24

(ii) (-3)² x (-5)²

Solution:-

Above question can be written as,

= (-3) x (-3) x (-5) x (-5)

= 9 x 25

= 225

(iii) (-2)³ x (-10)⁴

Solution:-

Above question can be written as,

= (-2) x (-2) x (-2) x (-10) x (-10) x (-10) x (-10)

= -8 x 10000

= -80000

(iv) (-1)⁹

Solution:-

Above question can be written as,

= (-1) x (-1) x (-1) x (-1) x (-1) x (-1) x (-1) x (-1) x (-1)

= -1

(v) 25² x (-1)³¹

Solution:-

Above question can be written as,

= 25 x 25 x (-1)

= 625 x (-1)

= -625

(vi) 4² x 3³ x (-1)¹²²

Solution:-

Above question can be written as,

= 4 x 4 x 3 x 3 x 3 x 1

= 16 x 27 x 1

= 432

6. Identify the greater number in each of the following:

(i) 4³ or 3⁴

Solution:-

Above question can be written as,

4 x 4 x 4 = 64

3 x 3 x 3 x 3 = 81

By comparing the two results,

3⁴ is the greater number.

(ii) 7³ or 3⁷

Solution:-

Above question can be written as,

7 x 7 x 7 = 343

3 x 3 x 3 x 3 x 3 x 3 x 3 = 2,187

By comparing the two results,

3⁷ is the greater number.

(iii) 4⁵ or 5⁴

Solution:-

Above question can be written as,

4 x 4 x 4 x 4 x 4 = 1024

5 x 5 x 5 x 5 = 625

By comparing the two results,

4⁵ is the greater number.

(iv) 2¹⁰ or 10²

Solution:-

Above question can be written as,

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 1024

10 x 10 = 100

By comparing the two results,

2¹⁰ is the greater number.

7. Write the following numbers as power of 2:

(i) 8

Solution:-

8 can be write as power of 2,

2 x 2 x 2 x 2 = 2⁴

(ii) 128

Solution:-

128 can be write as power of 2,

2 x 2 x 2 x 2 x 2 x 2 x 2 = 2⁷

(iii) 1024

Solution:-

1024 can be write as power of 2,

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2¹⁰

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ML Aggarwal Solutions for Class 7 Maths Chapter 4- Exponents and Powers

Download PDF: ML Aggarwal Solutions for Class 7 Maths Chapter 4- Exponents and Powers PDF

Chapterwise ML Aggarwal Solutions for Class 7 Maths :

• Chapter 1- Integers
• Chapter 2- Fractions and Decimals
• Chapter 3- Rational Numbers
• Chapter 4- Exponents and Powers
• Chapter 5- Sets
• Chapter 6- Ratio and Proportion
• Chapter 7- Percentage and Its Applications
• Chapter 8- Algebraic Expressions
• Chapter 9- Linear Equations and Inequalitie
• Chapter 10- Lines and Angles
• Chapter 11- Triangles and its Properties
• Chapter 12- Congruence of Triangles
• Chapter 13- Practical Geometry
• Chapter 14- Symmetry
• Chapter 15- Visualising Solid Shapes
• Chapter 16- Perimeter and Area
• Chapter 17- Data Handling

About ML Aggarwal

M. L. Aggarwal, is an Indian mechanical engineer, educator. His achievements include research in solutions of industrial problems related to fatigue design. Recipient Best Paper award, Manipal Institute of Technology, 2004. Member of TSTE.