CBSE Secondary (10th) Private Session 2025-26 Free Open Access

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss

Class 7: Maths Chapter 11 solutions. Complete Class 7 Maths Chapter 11 Notes. RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss RS Aggarwal 7th Maths Chapter 11, Class 7 Maths...

Curriculum CBSE
Applicable Grade Class 7
Medium English & Hindi
Resource Format Chapter Q&A / PDF

Textbook Solutions & Academic Guide

Verified chapter-wise solutions, answers, and study notes

Curriculum & Exam Preparation Note: Regular practice of NCERT textbook exercises and chapter-end questions establishes strong conceptual clarity for primary and secondary examinations.

Class 7: Maths Chapter 11 solutions. Complete Class 7 Maths Chapter 11 Notes.

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss

RS Aggarwal 7th Maths Chapter 11, Class 7 Maths Chapter 11 solutions

Ex 11A Solutions

Question 1.
Solution:
(i) C.P. = Rs. 950

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 1
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 1
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 1

Question 2.
Solution:
(i) CP = Rs. 2400
SP = Rs. 2592
Gain = SP – CP = Rs. 2592 – Rs. 2400 = Rs. 192

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 2
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 2

Question 3.
Solution:
(i) S.P. = Rs. 924
Gain% = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 3
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 3
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 3

Question 4.
Solution:
C.P. of an almirah = Rs. 13600
Amount spent on transportation = Rs. 400
Total cost price (CP) = Rs. 13600 + Rs. 400 = Rs. 14000
SP = Rs. 16800
Total gain = SP – CP
= Rs. 16800 – Rs. 14000 = Rs. 2800

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 4

Question 5.
Solution:
CP of an old house = Rs. 765000
Amount spent on repairs = Rs. 115000
Total cost price (CP) = Rs. 765000 + Rs. 115000 = Rs. 880000
Gain = 5%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 5

Question 6.
Solution:
CP of 1 dozen or 12 lemons = Rs. 25
SP of 5 lemons = Rs. 12

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 6

Question 7.
Solution:
SP of 12 pens = CP of 15 pens
Let CP of 1 pen = Re. 1
The CP of 15 pens = Rs. 15
and SP of 12 pens = Rs. 12

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 7

Question 8.
Solution:
SP of 16 spoons = CP of 15 spoons
Let CP of 1 spoon = Re. 1
Then CP of 15 spoons = Rs. 15
and SP of 16 spoons = Rs. 15

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 8

Question 9.
Solution:
For Manoj
CP of video = Rs. 12000
Gain = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 9
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 9

Question 10.
Solution:
SP of sofa set = Rs. 21600
Gain = 8%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 10

Question 11.
Solution:
SP of a watch = Rs. 11400
Loss = 5%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 11

Question 12.
Solution:
SP of calculator = Rs. 1325
Gain = 6%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 12
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 12

Question 13.
Solution:
SP of computer = Rs. 24480
Loss = 4%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 13

Question 14.
Solution:
In first case gain =15%
and in second case, gain = 20%
Difference = 20 – 15 = 5%
Now 5% of the CP = Rs. 108
CP = 108x1005 = Rs. 2160

Question 15.
Solution:
In first case, loss = 8%
and in second case gain = 6%
Difference = 8 + 6 = 14%
Now 14% of CP = Rs. 3360
CP = Rs. 3360x10014 = Rs. 24000

Question 16.
Solution:
SP of first cycle = Rs. 2376
Gain = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 16
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 16

Question 17.
Solution:
SP of an exhaust fan = Rs. 7350

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 17

Question 18.
Solution:
Let CP of watch for Mohit = Rs. 100
Gain =10%
SP for Mohit = Rs. 100 + 10 = Rs. 110
CP for Karim = Rs. 110
Gain = 4%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 18

Question 19.
Solution:
Retail price or S.P. of the machine for retailer = Rs. 37950
Gain = 25%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 19
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 19

Question 20.
Solution:
CP of video = Rs. 20000
and CP of television = Rs. 30000
Loss on video = 5%
and gain on TV = 8%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 20

Total CP of video and TV = Rs. 20000 + 30000 = Rs. 50000
and SP of video and TV = Rs. 190000 + 32400 = RS. 51400
Gain = SP – CP = Rs. 51400 – 50000 = Rs. 1400

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 20
RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 20

Question 21.
Solution:
SP of 36 oranges = CP of 36 oranges – loss = CP of 36 oranges – SP of 4 oranges
⇒ SP of 36 oranges + SP of 4 oranges = CP of 3 6 oranges
⇒ SP of 40 oranges = CP of 36 oranges
Let CP of each orange = Re. 1
CP of 36 oranges = Rs. 36
and SP of 40 of 40 oranges = Rs. 36

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 21

Question 22.
Solution:
We know that C.P. = S.P. – gain
C.P. of 8 dozen pencils = S.P. of 8 dozen pencils – S.P. of 1 dozen pencils
= S.P. of 7 dozen pencils = Rs. 100 (suppose)
C.P. of 1 dozen = Rs.1008

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11A Question 22

Ex 11B Solutions

Objective Questions :
Mark (✓) against the correct answer in each of the following :
Question 1.
Solution:
(b)
C.P. = Rs. 80
S.P. = Rs. 100
Gain = S.P. – C.P. = Rs. 100 – 80 = Rs. 20

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 1

Question 2.
Solution:
(a)
C.P. = Rs. 120
S.P. = Rs. 105
Loss = C.P. – S.P. = Rs. 120 – 105 = Rs. 15

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 2

Question 3.
Solution:
(b)
S.P. = Rs. 100
Gain = Rs. 20
C.P. = S.P. – gain = Rs. 100 – 20 = Rs. 80

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 3

Question 4.
Solution:
(a)
S.P. = Rs. 198
Gain = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 4

Question 5.
Solution:
(a)
First S.P. of jug = Rs. 144
Loss = 17 of C.P.
Let C.P. = x

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 5

Question 6.
Solution:
(d)
First S.P. of a pen = Rs. 48
Loss = 20%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 6

Question 7.
Solution:
(a)
C.P. of 12 pencils = S.P. of 15 pencils = Re 1 (suppose)

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 7

Question 8.
Solution:
(d)
Let CP of 4 toffees = SP of 3 toffee = Rs. 12
(LCM of 4, 3 = 12)
CP of 1 toffee = Rs. 124 = Rs. 3
SP of 1 toffee = Rs. 123 = 4
Gain = Rs. 4 – 3 = Re 1

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 8

Question 9.
Solution:
(c) SP of an article = Rs. 144
Loss% = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 9

Question 10.
Solution:
(a)
CP of 6 lemons = Re 1
CP of 1 lemon = Re 16
SP of 4 lemons = Re 1
SP of 1 lemon = Re 14

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 10

Question 11.
Solution:
(d)
SP of chair = Rs. 720
Gain% = 20%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 11

Question 12.
Solution:
(c)
SP of stool = Rs. 630
Loss% = 10%

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss Ex 11B Question 12

RS Aggarwal Solutions for Class 7 Maths Chapter 11: Download PDF

RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss

Download PDF: RS Aggarwal Solutions for Class 7 Maths Chapter 11–Profit and Loss PDF

Chapterwise RS Aggarwal Solutions for Class 7 Maths :

About RS Aggarwal Class 7 Book

Investing in an R.S. Aggarwal book will never be of waste since you can use the book to prepare for various competitive exams as well. RS Aggarwal is one of the most prominent books with an endless number of problems. R.S. Aggarwal's book very neatly explains every derivation, formula, and question in a very consolidated manner. It has tonnes of examples, practice questions, and solutions even for the NCERT questions.

He was born on January 2, 1946 in a village of Delhi. He graduated from Kirori Mal College, University of Delhi. After completing his M.Sc. in Mathematics in 1969, he joined N.A.S. College, Meerut, as a lecturer. In 1976, he was awarded a fellowship for 3 years and joined the University of Delhi for his Ph.D. Thereafter, he was promoted as a reader in N.A.S. College, Meerut. In 1999, he joined M.M.H. College, Ghaziabad, as a reader and took voluntary retirement in 2003. He has authored more than 75 titles ranging from Nursery to M. Sc. He has also written books for competitive examinations right from the clerical grade to the I.A.S. level.

FAQs

Why must I refer to the RS Aggarwal textbook?
RS Aggarwal is one of the most important reference books for high school grades and is recommended to every high school student. The book covers every single topic in detail. It goes in-depth and covers every single aspect of all the mathematics topics and covers both theory and problem-solving. The book is true of great help for every high school student. Solving a majority of the questions from the book can help a lot in understanding topics in detail and in a manner that is very simple to understand. Hence, as a high school student, you must definitely dwell your hands on RS Aggarwal!

Why should you refer to RS Aggarwal textbook solutions on Indcareer?
RS Aggarwal is a book that contains a few of the hardest questions of high school mathematics. Solving them and teaching students how to solve questions of such high difficulty is not the job of any neophyte. For solving such difficult questions and more importantly, teaching the problem-solving methodology to students, an expert teacher is mandatory!

Does IndCareer cover RS Aggarwal Textbook solutions for Class 6-12?
RS Aggarwal is available for grades 6 to 12 and hence our expert teachers have formulated detailed solutions for all the questions of each edition of the textbook. On our website, you'll be able to find solutions to the RS Aggarwal textbook right from Class 6 to Class 12. You can head to the website and download these solutions for free. All the solutions are available in PDF format and are free to download!

Read More

NCERT Solutions for All Classes (1 to 12)

Jump to free NCERT solutions, chapter Q&A, and textbooks for any grade

Popular Reference Solutions & Help Books

Step-by-step solutions for Mathematics and Science reference textbooks

Latest School & Board Updates

Real-time date sheets, admit cards, syllabus revisions, and exam notifications

Haryana Board Senior Secondary (12th) 20 Feb 2025
HBSE 12th 2024 Question Papers
View
Haryana Board Secondary (10th) 20 Feb 2025
HBSE 10th 2024 Question Papers
View
Haryana Board Senior Secondary (12th) 19 Feb 2025
HBSE 9th Model Papers 2025
View
Haryana Board Senior Secondary (12th) 19 Feb 2025
HBSE 11th Model Papers 2025
View
State Board Primary (1-5) 15 Feb 2025
BHU SET 2025 Application Form
View

Frequently Asked Questions

Common queries regarding NCERT textbook solutions & school curriculum

Are these NCERT solutions available 100% free of charge?

Yes. All NCERT solutions, chapter questions, textbook exercises, and download guides published on IndCareer Schools are completely free for students, parents, and educators without requiring any paid subscription or login.

Which subjects are covered for Class 7?

For Class 1, comprehensive NCERT solutions are provided for Mathematics (Math-Magic / गणित का जादू), English (Marigold & Mridang), and Hindi (Rimjhim / रिमझिम), alongside printable worksheets and textbook PDF downloads.

Are these solutions updated according to the latest CBSE / NCERT guidelines?

Yes. Our academic editorial team continually aligns all solutions and textbook references with the latest National Education Policy (NEP) and the rationalized curriculum issued by NCERT and the Central Board of Secondary Education (CBSE).

How can I download the official NCERT books in PDF format?

You can access official NCERT textbooks by clicking on the textbook links provided in the study content section above or by visiting the Class 1 to 12 NCERT Directory on IndCareer Schools.