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Maharashtra Board Solutions Class 5-Maths (Problem Set 20) - Part 1: Chapter 5- Fractions

Class 5: Maths Chapter 5 solutions. Complete Class 5 Maths Chapter 5 Notes. Maharashtra Board Solutions Class 5-Maths (Problem Set 20) - Part 1: Chapter 5- Fractions Maharashtra Board 5th Maths...

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Class 5: Maths Chapter 5 solutions. Complete Class 5 Maths Chapter 5 Notes.

Maharashtra Board Solutions Class 5-Maths (Problem Set 20) - Part 1: Chapter 5- Fractions

Maharashtra Board 5th Maths Chapter 5, Class 5 Maths Chapter 5 solutions

Important Questions and Answers.

Question 1.
Add the following
 (1) 15+35
Answer:

15+35=1+35=45

 (2) 27+47
Answer:

27+47=2+47=67

 (3) 712+212
Answer:

712+212=7+212=912

 (4) 29+79
Answer:

29+79=2+79=99=1

 (5) 315+415
Answer:

315+415=3+415=715

 (6) 27+17+37
Answer:

27+17+37=2+1+37=67

 (7) 210+410+310
Answer:

210+410+310=2+4+310=910

 (8) 49+19
Answer:

49+19=4+19=59

 (9) 58+38
Answer:

58+38=5+38=88=1

Question 2.
Mother gave 38 of one guava to Meena and 28 of the guava to Geeta. What part of the guava did she give them altogether?
Solution:

38+28=3+28=58 given altogether
Answer:
58 part of guava given altogether

Question 3.
The girls of Std V cleaned 34 of a field while the boys cleaned 14. What part of the field was cleaned altogether?
Solution:

Girls cleaned + Boys cleaned
34+14=3+14=44=1
Answer:
Full whole field cleaned altogether.

Subtraction of like fractions

A figure is divided into 5 equal parts and 4 of them are colored. That is, 45 part of the figure is coloured.

Now, we remove the colour from one of the coloured parts. That is, we subtract 15 from 45. The remaining coloured part is 35. Therefore, 45 – 15 = 4−15 = 35.

When subtracting a fraction from another like fraction, we write the difference between the numerators in the numerator and the common denominator in the denominator.

Example (1) Subtract : 713 – 513

These two fractions have a common denominator. So, we shall subtract the second numerator from the first and write the denominator as it is.
713−513=7−513=213

Example (2) If Raju got 512 part of a sugarcane and Sanju got 312 part, how much was the extra part that Raju got?

To find out the difference, we must subtract.
512−312=5−312=212. Thus, Raju got 212 extra.

Additional Important Questions and Answers

 (1) 36+26+16
Answer:

36+26+16=3+2+16=66=1

 (2) 410+110+310+210
Answer:

410+110+310+210=4+1+3+210=1010=1

 (3) 12+12
Answer:

12+12=1+12=22=1

Solve the following word problems:

Question 1.
of journey travelled by A and of journey travelled by B. What part of the journey travelled by both field was cleaned altogether?
Solution:

Travelled by A + Travelled by B
35+25=3+25=55=1
Answer:
Full (whole) journey travelled by both.

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Maharashtra Board Solutions Class 5-Maths (Problem Set 20) - Part 1: Chapter 5- Fractions

Download PDF: Maharashtra Board Solutions Class 5-Maths (Problem Set 20) - Part 1: Chapter 5- Fractions PDF

Chapterwise Maharashtra Board Solutions Class 5 Maths :

Part 1

Part 2.

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